Question

calculate the volume occupied by 5 mole O2 at STP​

Answer 1

Answer:

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0.00833 g CH4 x (1 mol CH4/16.0 g CH4) = 0.000521 mol CH4 = 0.521 mmol CH4

The volume occupied at STP is 0.521 mmol gas x (22.4 mL/mmol) = 11.7 mL

Note: The metric prefix, milli, is a number (1/1000 or 0.001). Thus, one can multiply and divide quantities by “m”. At STP, one mol of Ideal Gas occupies 22.4 L and one mmol of Ideal Gas occupies 22.4 mL.