calculate the volume occupied by 53.5 g of cl2
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1 molecule of Cl2(71g)=22.4lit
53.5g of cl2= 535×224/7100
=16.8lit(at stp) if not at stp 16.8/6.023×10^23
53.5g of cl2= 535×224/7100
=16.8lit(at stp) if not at stp 16.8/6.023×10^23
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