Question

Calculate the volume occupied by 6.02x10^25 molecules of oxygen at STP
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Answer 1

Assuming that the gas is at standard temperature and pressure (STP), one mole of any gas occupies 22.4 L . This means the number of moles of O2 is 222.4=0.089 mol .

Answer 2

Answer:-

2238.6 L

Explanation:-

Number of moles in 6.02×10²³ molecules of oxygen :-

= No of molecules/Avogadro Number

= 6.02×10²⁵/6.02×10²³

= 10²⁵/10²³

= 100 moles

Now, according to Ideal gas equation, we know that :-

PV = nRT

Where :-

• P is the pressure .

• V is the volume occupied by the gas.

• n is the number of moles of the gas.

• R is Ideal Gas Constant [0.082]

• T is the temperature.

Also, at STP :-

• P = 1 atm

• T = 273 K

Substituting values, we get :-

=> 1 × V = 100 × 0.082 × 273

=> V = 2238.6 L

Thus, the required volume of oxygen is 2238.6L .

Some Extra Information:-

The combination of various laws namely Boyle's Law, Charle's Law and Avogadro's Law leads to the development of the mathematical relation which relates four variables pressure, volume, moles of ideal gas and temperature. The equation so formulated is called Ideal Gas Equation .