Question

calculate the volume occupied by 64 gram of oxygen at STP​

Answer 1

Answer:

Given:

64 grams of oxygen has been provided at STP (Standard Temperature and Pressure)

To find:

Volume occupied by the gas

Concept:

We should always remember this relationship :

1 mole of gas occupies 22.4 L volume at STP irrespective of the type of gas.

Calculation:

Number of moles of oxygen

= (given Mass)/(Molar Mass)

= 64/32

= 2 moles.

Now applying Unitary Method:

At STP, 1 mole occupies 22.4 L

∴ 2 moles occupy 22.4 × 2 = 44.8 L

So the final answer is 44.8 L

Answer 2

Answer:

Molecular mass of oxygen = 32 grams.

No. of moles of oxygen = 64/32 = 2 moles.

1 moles takes 22.4 L volume at STP

Hence, 2 moles will take 22.4 * 2 = 44.8 L

Answer: 44.8 L