Question

Calculate the volume occupied by 64g of oxygen

Answer 1

64/32= 2 moles
1mole contain 22.4
2*22.4L= 44.8 L

Answer 2

One mole of a gas occupies 22.4 L volume at STP

Now, number of moles in 64 g oxygen gas = 64/32 = 2

Therefore, volume occupied by 2 moles(64 g) of oxygen gas = 2 x 22.4 L = 44.8 L

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