Question

calculate the volume occupied by 8.8g of co2 at 31.1°C and 1bar pressure. R=0.083 bar L K^-1 mol^-1.

Answer 1

From Ideal gas eqn,
PV=nRT
So
To find volume,
V=nRT/P

Hope you got it

Answer 2

8.8 g of $CO_2$ at 31.1°C and 1 bar pressure occupies volume of 5.05 L.

Given:

Weight of $CO_2$ (w) = 8.8 g

Pressure (P) = 1 bar

Temperature = 31.1°C = (273 K + 31.1) = 304.1 K

R = $0.083 bar L K^-1 mol^-1$

To find:

Volume (v) = ?

Formula to be used:

$PV = \frac{w}{M}\times RT$

Calculation:

Molecular weight of $CO_2$ = 1 (Atomic weight of carbon) + 2 (Atomic weight of oxygen)

Molecular weight of $CO_2$ = 1 (12) + 2(16)

Molecular weight of $CO_2$ = 12 + 32

Molecular weight of $CO_2$ = 44

We know that as per gas equation:

$PV = \frac{w}{M}\times RT$

Substituting the given values in the formula gives

1 × V = $\frac{8.8}{44} \times 0.083\times 304.1$

1 × V = 0.2 × 0.083 × 304.1

V = $\frac{0.2\times 0.083 \times 304.1}{1}$

V = 5.04806 = 5.05

Conclusion:

The volume occupied by 8.8 g of $CO_2$ at 31.1°C and 1 bar pressure is calculated as 5.05 L.

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