Question

calculate the volume occupied by 88 gm of CO2 at STP?​

Answer 1

Answer:

Calculate the volume occupied by 8.8 g of CO2 at 31.1°C and 1 bar pressure. R = 0.083 bar L K–1 mol–1. Hence, the volume occupied is 5.05 L.

Answer 2

Given :

Mass (m) = 88 gm

To Find :

Volume occupied by 88 gm of CO2 at STP

Solution :

At STP, 1 mole of any gaseous substance occupies a volume of 22.4 L

We know, 1 mole of CO₂ = 44 gm of CO₂

So,

Volume occupied by 44 gm of CO₂ = 22.4 L

Volume occupied by 88 gm of CO₂ = $\frac{22.4}{44}$ × 88 L

                                                           = 44.8 L

Therefore, the volume occupied by 88 gm of CO₂ is 44.8 L