Question

calculate the volume occupied by 8g of SO2

Answer 1

molar mass of SO2=32+(16x2)=64 gmol-1
Volume occupied by 32 grams of So2=22.4 l
volume occupied by 8 g of So2=(22.4x 8)/32
=5.6 litres
∴volume occupied by 8f of S02 is 5.6 lit

Answer 2

Given data:
Molar mass of SO2=32+(16x2)
=64 gmol-1
Volume occupied by 32 grams of So2
=22.4 l
volume occupied by 8 g of So2=(22.4x 8)/32 
=5.6 litres
∴volume occupied by 8f of S02 is 5.6 lit