Calculate the volume occupied by a gram mole of a gas at 10°C and pressure of 1 atm
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Answered by
29
Answer:
V = 23.07 L
Explanation:
Given :
Pressure ( P ) = 1 atm
Temperature ( T ) = 10 C or 283 K
No. of moles ( n ) = 1 mol
We have to calculate volume of gas :
We have ideal gas equation :
P V = n R T
Value of R = 0.0821 L mol⁻¹ K⁻¹
Putting values here :
V = n R T / P
V = 1 × 0.0821 × 281 / 1
V = 0.0821 × 281 L
V = 23.07 L
Hence we get volume of gas is 23.07 L
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Answer:
Explanation:
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