Question

Calculate the volume of 0.015 m hcl solution required to prepare 250ml of a5.25×10-3m hcl solution

Answer 1

Answer: 87.5 ml

Explanation:

According to the dilution law,

$M_1V_1=M_2V_2$

where,

$M_1$ = molarity of stock solution = 0.015 M

$V_1$ = volume of stock solution =?

$M_2$ = molarity of resulting solution = $5.25\times 10^{-3}$ M

$V_2$ = volume of resulting solution = 250 ml

Putting in the values we get:

$0.015M\times V_1=5.25\times 10^{-3}\times 250$

$V_1=87.5ml$

Therefore, the volume of 0.015 m $HCl$ solution required to prepare 250ml of a $5.25\times 10^{-3}$ M  $HCl$ solution is 87.5 ml.