Question

CALCULATE the volume of 0.05 M KMNO4 SOLUTION REQUIRED TO OXIDISE COMPLETELY 2.70g of oxalic acid in acidic medium .(H2 C2 O4)

Answer 1

Answer:

Balanced equation for the redox reaction is: 2KMnO4 + 5(COOH)2 + 3H2SO4 → K2SO4 + 2MnSO4 + 10CO2 + 8H2O No of moles oxalic acid = 2.70/90 = 0.03 mole From the balanced equation, 5 moles of (COOH)2 = 2 mole KMnO4 Then 0.03 mole (COOH)2 = 0.012 moles of KMnO4. Now, 0.05 mole of KMnO4 is present in solution given = 1000 cm3. 0.012 mole of KMnO4 is present in solution = 2525 = 240 cm3