Question

Calculate the volume of 0.1 M FeSO4 reacted with 20 ml of 0.2 N K2Cr2O7 in acidic medium

Answer 1

the volume of 0.1 M FeSO4 is 40ml in acidic medium

Answer 2

Answer:

Explanation:

k2Cr2o7 => strong oxidising agent

↓H⁺

       

   ↓⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻↓
Cr₂0₇²⁻                   Cr⁺³       ny = 3*2

2x+7(-2) = -2                        ny = 6

2x= -12

x = 6

FeSO₄

↓⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻↓

Fe⁺²  --------------->Fe⁺³   ny = 1*1 = 1

Law of equivalence

k2Cr2o7  N₁V₁ = N₂V₂  FeSO₄       N = m *ny

                  0.2*20 = 0.1*V₂                                   N = 0.1*1

                       V₂ = 0.2*20/0.1                                N = 0.1

                     V₂ = 20*2 = 40 ml

     V₂ = 40 ml