Question

calculate the volume of 0.1 m KMnO4 required to react with 100 ml of 0.1 m H2C2o4.2H2O solution in the presence of H2so4​

Answer 1

Answer:

it react with 5 moles of oxalic acid

Explanation:

2kmno4+5h2c2o4.2h2o=2mnso4k2so4+ 10co2+10h2o

Two moles of kmno4 react with 5 moles of oxolic acid

m1v1=m2v2

2(0.1×v1) =5(0.1×100)

0.2×v1=50

x=250.