Question

Calculate the volume of 0.1M KMnO4 required to react with 100ml of

0.1M H2C2O4.2H2O solution in the presence of H2SO4​

Answer 1

Answer:

2KMnO

4

+5H

2

C

2

O

4

.2H

2

O+H

2

SO

4

⇌2MnSO

4

+K

2

SO

4

+10CO

2

+10H

2

O

Two moles of KMnO

4

reacts with 5 moles of oxalic acid.

M

1

V

1

=M

2

V

2

2(0.1∗V

1

)=5(0.1∗100)

0.2∗V

1

=50=>x=250ml