Question

Calculate the volume of 0.1N H2so4 required to neutralize 200ml of 0.2N NaoH solution

Answer 1

Answer:

based on the formula of normalitys

Answer 2

The volume of $H_2SO_4$ required is 400 ml .

Given :

Normality of $H_2SO_4$ is , $N_1=0.1 \ N$ .

Normality of NaOH is , $N_2=0.2 \ N$ .

Volume of NaOH is , $V_2=200\ ml$ .

Let , volume of $H_2SO_4$ required to neutralize the NaOH is $V_2$ .

We know , their equivalent must be equal .

Equivalent is given as product of normality and volume , so :

$N_1V_1=N_2V_2\\0.1\times V_1=0.2\times 200\\\\V_1=\dfrac{0.2\times 200}{0.1}\\\\V_1=400\ ml$

Hence , this is the required solution .

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