Question

calculate the volume of 0.2 Mol of Sulphur dioxide at STP​

Answer 1

Answer:

1 mole ........22.4 L

0.2 mole........22.4× 0.2/1= 4.48 L

Answer 2

Dear Student,

◆ Answer -

Volume of SO2 = 4.48 L

● Explaination -

We know that 1 mol of ideal gas at STP measures 22.4 L volume.

Volume of 0.2 mol of SO2 is -

V = n × 22.4

V = 0.2 × 22.4

V = 4.48 L

Therefore, Volume of 0.2 mol of SO2 is 4.48 L.

Thanks dear. Hope that helps you..