Question

Calculate the volume of
0.3 moles of HCl
4.4g of CO₂
34g of NH₃

Answer 1

Answer:

We know that volume of 1 mole = 22.4 litres

i)0.3 moles of HCl = 0.3 x 22.4 = 6.72 l

ii) 4.4 g of CO₂ = 4.4/44 = 0.1 moles

Volume = 0.1 x 22.4 = 2.24 l

iii) 34 g of NH₃ = 34/17 = 2 moles

Volume = 2 x 22.4 = 44.8 l

Answer 2

Answer:

Explanation:

We know that at RTP the constant volume is 24 dm^3 and at STP the volume is 22.4 litres.

I am showing for RTP, you can slove in the same way for STP by changing the value from 24 to 22.4 and the respective unit.

a) 0.3 moles of HCl

0.3 X 24 = 7.2 dm^3

b) 4.4g of CO2

Molar mass of CO2 = 12 + 16 X 2 = 12 + 32 = 44

Number of mole = Mass/Molar mass = 4.4/44 = 0.1

Volume = 0.1 X 24 = 2.4 dm^3

c) 34g of NH₃

Molar mass of NH3 = 14 + 1 X 3 = 14 + 3 = 17

Number of mole = Mass/Molar mass = 34/17 = 2

Volume = 2 X 24 = 48 dm^3

I hope it helps.... Good luck.