Calculate the volume of 0.5 mol/dm³ H2SO4 that is neutralized by 25cm³ of 0.1 mol/dm³ NaOH
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Answered by
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Answer:
2.5cm³
Explanation:
H2SO4+2NaOH⇒Na2SO4+2H20
CaVa/CbVb= Na/ Nb
Ca=0.5mol
Cb=0.1mol
Va=?
Vb=25cm³
Na=1
Nb=2
Va=Cb×Vb×Na/Ca×Nb
Va=0.1×25×1/0.5×2
Va=2.5cm³
Answered by
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H2SO4+2NaOH----->Na2SO4+2H20
CaVa/CbVb= Na/ Nb
Ca=0.5mol/don't
Cb=0.1mol/dm3
Va=?
Vb=25cm³
Na=1
Nb=2
Va=Cb×Vb×Na/Ca×Nb
Va=0.1×25×1/0.5×2
Va=2.5cm³
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