Chemistry, asked by HimeSama, 5 hours ago

Calculate the volume of 0.5 mol/dm³ H2SO4 that is neutralized by 25cm³ of 0.1 mol/dm³ NaOH​

Answers

Answered by amani1132007
0

Answer:

2.5cm³

Explanation:

H2SO4+2NaOH⇒Na2SO4+2H20

CaVa/CbVb= Na/ Nb

Ca=0.5mol

Cb=0.1mol

Va=?

Vb=25cm³

Na=1

Nb=2

Va=Cb×Vb×Na/Ca×Nb

Va=0.1×25×1/0.5×2

Va=2.5cm³

Answered by atharva3131
0

H2SO4+2NaOH----->Na2SO4+2H20

CaVa/CbVb= Na/ Nb

Ca=0.5mol/don't

Cb=0.1mol/dm3

Va=?

Vb=25cm³

Na=1

Nb=2

Va=Cb×Vb×Na/Ca×Nb

Va=0.1×25×1/0.5×2

Va=2.5cm³

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