Question

calculate the volume of 1.5 molar HCL which reacts with 2.4 gram magnesium completely????​

Answer 1

Answer:

Explanation:

       Mg + 2HCl -----> MgCl2 + H2

     24 gm   73 gm

given  0.1 mol    1.5 M x V

             then M1 V1 = M2 V2

                 0.1 x 22.4 = 1.5 V     ( 1 mole occupies 22.4 lit)

             V = 1.5 lit (approx )

         hope u get it n let me know...............................