Question

calculate the volume of 1 mole of a gas at exactly 20 degree celsius at a pressure of 101.35 kPa

Answer 1

Hi,

Answer:

The volume of gas is 24.055 L.

Explanation:

Given data:

No. of moles of gas, n = 1

Absolute temperature, T = 20° C = 20 + 273.15 K = 293.15 K

Pressure, P = 101.35 kPa = 101.35 * 10³ Pa = 101.35 * 10³ * 9.869 * 10⁻⁶ = 1 atm ....... [∵ 1 Pa = 9.869 * 10⁻⁶ atm]

To find: Volume, V

Using the ideal gas law, we get

PV = nRT

Where, R = ideal gas constant = 0.08206 L. atm. mol−1

∴ V = n(RT/V)

Or, V = 1 * [(0.08206 * 293.15) / 1] = 24.055 L

Hope this helps!!!!!

Answer 2

Answer:24.055L

Explanation:NO. OF MOLES OF GAS, n=1

absolute temprature. T= 20degree celcius = 20 + 273.15K = 293.15K; THEREFORE, USING IDEAL GAS LAW; PV=nRT ; HENCE, R= IDEAL GAS CONSTANT 0.08206L V= n(RT/V) SO HERE, V= 1*[(10.08206*293.15)/1] = 24.055L.