Calculate the volume of 1 mole of oxygen at 27°C and 1 atm pressure.The molar volume of oxygen at NTP is 22.4l mol.
Answers
Answered by
1
the volume will be
6.15
liters.
Explanation:
We use the ideal gas equation, which states that
P
V
=
n
R
T
We need to solve for volume, so rearrange the equation into
V
=
n
R
T
P
We use the given values for this question, which is
n
=
1
mol
R
=
0.082
L
atm
K
−
1
mol
−
1
T
=
300
K
P
=
4
atm
We get:
V
=
1
mol
⋅
0.082
L
atm
K
−
1
mol
−
1
⋅
300
K
4
atm
=
6.15
L
So, the volume of the oxygen gas will be
6.15
liters or
6150
milliliters.
Of course, this would not be the exact value, as no gas behaves exactly like an ideal gas.
Answered by
0
Answer:
12.3L
Explanation:
calculate the volume of one mole of oxygen 27 degree celsius and two atmosphere.Molar volume of oxygen at STP is 22.4 liters
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