calculate the volume of 1 mole of solution of sodium hydroxide that is neutralized by 200 ml of 2 molar aqueous hydrochloric acid and the mass by Sodium Chloride produce
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Answer:
the volume of 1 mole of solution of sodium hydroxide = 400mL
the mass by Sodium Chloride produce = 23.4 g
EXPLANATION:
M1V1=M2V2
1×V=2×200
V=400mL
NaOH + HCl = NaCl + H2O
Number of moles of NaOH = Number of moles of NaCL
0.4 L of 1 M NaOH contains o.4 mol NaOH which would produce 0.4 mol NaCl
Therefore Mass of NaCl produced = 0.4 x 58.5 = 23.4
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