Question

calculate the volume of 10 mole of ammonia at stp

Answer 1

Moles of 140g N₂ = 140 / 28 = 5

Moles of 30g H₂ = 30 / 2 = 15

Balanced Equation for formation of Ammonia:

N₂ + 3H₂ ==> 2NH₃

From above equation we can say……,

5 moles of nitrogen and 15 moles of hydrogen when react will give 10 moles of Ammonia

Volume of 10 moles of Ammonia at STP

= 10 × 22.4 litres

= 224 litres

Volume of ammonia gas produced is 224 litres.

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