Question

calculate
the volume of 12N and 3N hcl required
to prepare 2 litre of 6N hcl solution
​

Answer 1

Answer:

n1=12,v1=v

n2=6,v2=2litre

n1×v1=n2×v2

12×v=6×2

v=1litre

n1=3,v1=v

n2=6,v2=2litre

n1×v1=n2×v2

3×v=6×2

v=4litre