Calculate the volume of 14.3m NH3, solution needed to prepare 1L
of 0.1M solution.
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Use this formula to simplify things:
m(a) * Volume (a) = m(b) * Volume (b)
(m is in moles/L and volume is in L)
14.3mol/L * ?L = 0.1mol/L * 1L
Becomes ? = 0.1/14.3
? = 0.0070L which is 7mL into total volume of 1L
m(a) * Volume (a) = m(b) * Volume (b)
(m is in moles/L and volume is in L)
14.3mol/L * ?L = 0.1mol/L * 1L
Becomes ? = 0.1/14.3
? = 0.0070L which is 7mL into total volume of 1L
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