Calculate the volume of 16 g of oxygen at 22°C and 97.5 kPa
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Answer:
Explanation: we know 16g of oxygen means 1 mole
That is 16/16=n
n=1
P=97.5
V=?
T=22°c=295k
We the expression that pv=nrt
Therefore v=nrt/p
r= 8.314
V=1×295×8.314/95.7
V=25.14
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