Question

Calculate the volume of 170g of NA3 at STP ( molecular mass-17 )

Answer 1

Answer:

$\large{\bf{\blue{\underline{\underline{Hii...!!}}}}}$

Given: Mass of ammonia at STP = 170g

Molecular mass of NH3 = 17g

First, we will calculate the number of moles by applying the formula given in the attachment

Number of moles = 10

Thus, number of moles of CaCO3 is 10

Now 1 mole of any gas occupies 22.4 litres of volume.

∴ 1 mole of NH3 = 22.4 litre

10 moles of NH3 = 22.4 × 10 = 224 litres

Thus, the volume occupied by 170g of NH3 is 224 litres.

$<svg width="100" height="90" viewBox="0 0 100 100">\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ <path fill="red" d="M92.71,7.27L92.71,7.27c-9.71-9.69-25.46-9.69-35.18,0L50,14.79l-7.54-7.52C32.75-2.42,17-2.42,7.29,7.27v0 c-9.71,9.69-9.71,25.41,0,35.1L50,85l42.71-42.63C102.43,32.68,102.43,16.96,92.71,7.27z"></path>\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ <animateTransform \ \textless \ br /\ \textgreater \ attributeName="transform" \ \textless \ br /\ \textgreater \ type="scale" \ \textless \ br /\ \textgreater \ values="1; 1.5; 1.25; 1.5; 1.5; 1;" \ \textless \ br /\ \textgreater \ dur="1s" \ \textless \ br /\ \textgreater \ repeatCount="40"> \ \textless \ br /\ \textgreater \ </animateTransform>\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ </svg>$

Answer 2

Answer:

heyy

Explanation:

ur ans is herre........