Question

Calculate the volume of 1M NaOH required to prepared 1000 mL of 0.2M NaOH solution

Answer 1

Answer:

molarity = no. of moles of solute / 1 liter .

* one moles of sodium hydroxide = 40 gm of sodium hydroxide.

so we can said ; if want prepare 1 molar NaOH solution then we need 40 gm NaOH dissolve in one liter of water so it became one 1 molar NaOH solution.

Explanation:

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Answer 2

Given: 1000 mL off 0.2 M NaOH solution and some volume of 1 M NaOH solution

To find: Volume of NaOH(1 M) required to prepare 1000 mL of 0.2 M solution

Explanation: The volume of 1 M solution required should have equal moles that the 1000 mL of 0.2 M solution has.

Volumes of 0.2 M solution= 1000 mL = 1L

Molar mass of NaOH= 40 g/mol

Moles of NaOH in 0.2 M solution

= Molarity * Volume(in L)

= 0.2 * 1

= 0.2 moles

Moles in 1 M NaOH solution

= Molarity * Volume (in L)

= 1* Volume (in L)

Now, since moles are equal

=> 1* Volume of 1 M solution= 0.2

=>Volume of 1 M solution= 0.2

Therefore, the volume of 1 M NaOH required to prepare 1000 mL of 0.2 M solution is 0.2 L or 200 mL.