Question

calculate the volume of 38% solution of
Hal to make a L of 0.1 m Ha solution
( Density of giver ha = 1.20 g/mol​

Answer 1

Answer:

density of solution = 1.19 glml  

Molarity =  

MolarmassofHCl

1.19

​  

×1000×38%

=  

36.5

1.19

​  

×1000×  

100

38

​  

 

12.389m

mole of HCl required to make 10 L of all 0.1MHCl=10×0.1=1mole

12.389×v=1

v=  

12.389

1

​  

=80.7ml

Explanation: