Calculate the volume of 4 g of H2 at 4 atmosphere.
Answers
Answered by
4
(Assuming the Temperature to be 273K)
As we know PV = nRT
Thus V = nRT/P
n = no of moles = 4/2 =2 (molar mass of H2=2)
Thus V = 2 x 0.082 x 273 / 4
= 11.193 Litres
As we know PV = nRT
Thus V = nRT/P
n = no of moles = 4/2 =2 (molar mass of H2=2)
Thus V = 2 x 0.082 x 273 / 4
= 11.193 Litres
Similar questions
Biology,
7 months ago
Social Sciences,
7 months ago
English,
7 months ago
Chemistry,
1 year ago
Science,
1 year ago