Chemistry, asked by chillamkurprasanna, 5 months ago

calculate the volume of 6×10^23 H2 molecules ​

Answers

Answered by mohanddr
1

Answer:

22.4 litre

Explanation:

By STP we mean

P= 1 bar

T= 273.15 K

For an ideal gas

PV = nRT

R= 8.314 Lbar K⁻¹ mol⁻¹

6.023×10^{23}10

23

molecules makes 1 mole

n = 1

V = 22.4 L.

NOTE: 1 MOLE OF ANY GAS AT STP OCCUPIES 22.4 L.

Answered by Devutty92
0

Answer:

22.4 litres

Explanation:

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