Chemistry, asked by dyan82, 10 months ago

Calculate the volume of 75% of H2SO4 by weight (d=1.8 gm/ml) required to prepare 1L of 0.2 M solution.​

Answers

Answered by Aks1705
7

Answer:

M1 V1=M2 V2

Volume=14.5ml

Attachments:
Answered by Sinthushaa
0

Answer:

Volume of H2 SO4 s 15.3 ml

Explanation:

75% of mass of H2SO4 = 75g

Molecular weight of H2SO4 = 98

μ= M/V = 75/98

M1V1 = M2V2

M = 75×1.8/98×75

= 0.013M

0.013×V1= 0.2×1

V1= 1×0.2/0.013

V1= 15.3 ml

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