Question

calculate the volume of 8 gram of oxygen under ntp condition

Answer 1

STP=22.4litres

Oxygen=8g

Volume of 8g of oxygen=

8*22.4=179.2 litres.

Answer 2

The volume of 8 grams of oxygen under NTP condition is 5.6 L

• At normal temperature and pressure (NTP) conditions, 1 mole of a substance occupies 22.4 L
• Therefore, 1 mole of oxygen occupies 22.4 L
• We know that 32 grams of oxygen equal 1 mole of oxygen
• Therefore, 8 grams of oxygen equals 1/4 mole of oxygen
• So, if 32 grams of oxygen occupies 22.4 L volume, then 8 grams of oxygen occupies (22.4)/4 = 5.6 L of volume under NTP conditions

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