Calculate the volume of 80% of h2 s o4 required to prepare 1 litre of 20% of h2 s o4
Answers
Answered by
110
How do I calculate the volume of 80% of H2SO4 by the weight (density= 1.8g/mol) required to prepare 1L of 0.2M solution?
Still have a question? Ask your own!
What is your question?
1 ANSWER

CHAITNAYA KUMAR, Chemist at Element Dynamics & geochemist at ONGC
Answered May 6, 2016 · Author has 92 answers and 52.1k answer views
There is a little correction in the question. Density of 80% sulphuric acid would be 1.8 g/ml not 1.8g/mol.
First you have to calculate the molarity of 80% acid solution which will act as stock solution.
By using the given density 1.8 g/mL
1800 g for 1 litre
Thus, 80% X 1800 =1440g acid required
Since, molarity = weight taken/ formulae weight
=> 1440/98.80= 14.68 M
Now you have molarity of your stock solution 14.68M
In next step you require 0.2 M acid solution from 14.68M stock solution.
You can use the formulae
M1 V1= M2V2
volume required (V1) = 0.2 X 1000 / 14.68
= 13.62 ml
13.62 ml of 80 % sulphuric acid is required.
Hope it helps u dud...
Still have a question? Ask your own!
What is your question?
1 ANSWER

CHAITNAYA KUMAR, Chemist at Element Dynamics & geochemist at ONGC
Answered May 6, 2016 · Author has 92 answers and 52.1k answer views
There is a little correction in the question. Density of 80% sulphuric acid would be 1.8 g/ml not 1.8g/mol.
First you have to calculate the molarity of 80% acid solution which will act as stock solution.
By using the given density 1.8 g/mL
1800 g for 1 litre
Thus, 80% X 1800 =1440g acid required
Since, molarity = weight taken/ formulae weight
=> 1440/98.80= 14.68 M
Now you have molarity of your stock solution 14.68M
In next step you require 0.2 M acid solution from 14.68M stock solution.
You can use the formulae
M1 V1= M2V2
volume required (V1) = 0.2 X 1000 / 14.68
= 13.62 ml
13.62 ml of 80 % sulphuric acid is required.
Hope it helps u dud...
Similar questions