calculate the volume of 900 gram of cooking oil whose density is 0.9g/cmsquare. express the answer in litres
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Answer:
The required volume is 1 L
Explanation:
900 g of cooking oil whose density is 0.9 g/cm³
To find :
the volume of the cooking oil
Solution :
Density of a substance is its mass per unit volume.
SI unit of density is kg/m³
It is expressed as,
\boxed{ \rm \rho =\frac{m}{V}}
ρ=
V
m
where
m denotes the mass
V denotes the volume
Substitute the given values,
0.9 g cm⁻³ = 900 g/V
V = 900 g/0.9 g cm⁻³
V = 1000 cm³
V = 1 L [ ∵ 1000 cm³ = 1 L ]
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