Question

Calculate the volume of 98% by mass HCl solution (density of the solution is 1.1 g/ml) required to produce 100 cm3 of 3 M of HCl solution

Answer 1

Answer:

density_mass/volume

1.1=100/v

Molarity=98/36.5/100/1.1

=xmolar suppose

using relation

M1V1=M2V2

M1=x

V1=?

M2 =3M

V2=100ml

Volume can be calculated

Answer 2

Answer:

10.11 mL

Explanation:

1000 cm3 3M HCl contains 3 mol or 3*36.5 g = 109.5 g of HCl.

So, 100 cm3 contains 10.95 g of HCl.

98.5 g of HCl is available in 100 g solution.

So, 10.95 g will be available in = (100*10.95)/98.5 g = 11.12 g solution

11.12 g solution = (11.12 g)/(1.1 g/mL) = 10.11 mL solution