Question

Calculate the volume of air required for complete combustion of 4L of Butane :-

Answer 1

Answer:

26L

Explanation:

the general equation for combustion is

CxHy+(x+y/4)O2 ------- y/2 H2+xCO2

so for Butane x=4,y=10

for , 1L of C4H10 -------6.5 L of O2

4L of C4H10 -------A L of O2

we get a = 26L