Question

Calculate the volume of air required to produce 35g of phosphorus(v) oxide during the combustion of an excess of posphorus

Answer 1

Answer:

Solution:- (C) 6.6 L

Given volume of acetylene =0.25dm

3

=2.64L

Combustion of acetylene (C

2

H

2

)-

2

(acetylene)

C

2

H

2

(g)

+5O

2

(g)

⟶4CO

2

(g)

+2H

2

O

(l)

As we know that volume of 1 mole of gas is 22.4 L.

Amount of oxygen required for the combustion of 44.8 L (2 moles) of acetylene =(5×22.4)L=112L

∴ Amount of oxygen required for the combustion of 2.64 L of methane =

44.8

112

×2.64=6.6L

Hence, 6.6 L of oxygen required for the complete combustion of 2.64 L of acetylene