Chemistry, asked by utkarsh5639, 1 year ago

calculate the volume of ammonia gas produced at stp when 140 g of N gas reacted with 30 g of H gas?

Answers

Answered by JunaidMirza
25
Moles of 140g N₂ = 140 / 28 = 5
Moles of 30g H₂ = 30 / 2 = 15

Balanced Equation for formation of Ammonia:
N₂ + 3H₂ ==> 2NH₃

From above equation we can say……,
5 moles of nitrogen and 15 moles of hydrogen when react will give 10 moles of Ammonia

Volume of 10 moles of Ammonia at STP
= 10 × 22.4 litres
= 224 litres

Volume of ammonia gas produced is 224 litres.
Answered by ashwaniani2002
7

Answer:224

Explanation:

No of moles in 140g Nitrogen=140/28=5

No of moles of hydregon=30/2=15

N2+3H2>2NH3

1:3:2

5:15:10

Volume of10 Mole of Ammonia At STP=10*22.4=224 L

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