Calculate the volume of ammonia gas produced at STP when 140 g of nitrogen gas reacts with 30 g of hydrogen gas. (Atomic mass =N=147u,H=1u)
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Answer:
(10 × 22.4 L = 224 L )
Explanation
.Simply, the reaction is N 2 + 3 H 2 = 2 N H3
140 g N 2 means 140 ÷28 = 5 mol;
30 g H 2 means 30 ÷2 = 15 mol
From 1 mol of N 2 2 mol N H 3 is prepared in perfect presence of H 2
Hence, 10 mol of N H 3 will be produced.
We know,1mol of any ideal gas at STP ( 0 ∘ C and 1 atm ) contains 22.4L of the ideal gas.
Produced ammonia is 224 L
.
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