Calculate the volume of amonia has produced st STP when 140g of nitrogen gas reacts with 30g of hydrogen gas.
Answers
Answer:
N
2
+3H
2
⟶2NH
3
Number of moles of N
2
in 140g=
28
140g
=5 moles of N
2
Number of moles of H
2
in 30g=
2
30
=15 moles of H
2
moles N
2
+3H
2
⟶2NH
3
at t=0 5 15 -
after reaction 5−5×1 15−3×5 2×5
Thus 10 moles of NH
3
produced after reaction
as number of moles=
volume at STP
volume of product
⇒10=
22.4L
V
⇒V=224L
Thus 224L of ammonia is produced.
Answer:
Explanation:
N
2
+3H
2
⟶2NH
3
Number of moles of N
2
in 140g=
28
140g
=5 moles of N
2
Number of moles of H
2
in 30g=
2
30
=15 moles of H
2
moles N
2
+3H
2
⟶2NH
3
at t=0 5 15 -
after reaction 5−5×1 15−3×5 2×5
Thus 10 moles of NH
3
produced after reaction
as number of moles=
volume at STP
volume of product
⇒10=
22.4L
V
⇒V=224L