calculate the volume of C02 liberated at STP and the quantity of heat energy liberated from the combustion of 2.3 g of ethyl alcohol
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Answered by
1
Answer:
Co^2=water..
combination height =2.3 kg
First calculate the quantity of water and combination of height...
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Answered by
2
Answer:
Explanation:
Molecular weight of ethyl alcohol
( C2H5OH) = 46
46g of ethyl alcohol on combustion liberate 2 × 22.4 lit of C02 at STP and 1367.2 of energy
Volume of CO2 liberatedby the combustion of 2.3g of ethyl alcohol
= 2.3/46 × 2 × 22.4
= 2.24L
Energy liberated
= 2.3/46 × 1367.2 = 68.36KJ
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