Question

Calculate the volume of carbon dioxide formed at STP by burning 10l of ethane gas.

Answer 1

Answer:

Write down the chemical equation for the combustion, namely:

2C2H6 + 7O2 = 4CO2 + 6H2O

From the molecular weights of the ethane and carbon dioxide, adjusted for the number of molecules in the balanced equation, you can determine the number of gram moles of CO2 formed from the combustion of x gram moles of C2H6 from the 10 litre volume.

You calculate the number of gram moles of ethane contained in 10 litres by assuming ideal gas behaviour, which is probably challenging the assumption that ethane acts like an ideal gas. But you really don’t have much option here!

Nevertheless, from the ideal gas equation you can derive that 1 gram mole of an ideal gas at STP occupies 22.4 litres. Therefore 10 litres are equivalent to x gram moles of ethane …… I’ll leave you to do the arithmetic.

You now have the basis for quantifying the volume of CO2 produced from the number of gram moles in 10 litres of ethane at STP from the above equation that states that 2 gram moles of ethane produce 4 gram moles of CO2.

Answer 2

Answer:

4 gram

Explanation:

Write down the chemical equation for the combustion, namely:

2C2H6 + 7O2 = 4CO2 + 6H2O

From the molecular weights of the ethane and carbon dioxide, adjusted for the number of molecules in the balanced equation, you can determine the number of gram moles of CO2 formed from the combustion of x gram moles of C2H6 from the 10 litre volume.

You calculate the number of gram moles of ethane contained in 10 litres by assuming ideal gas behaviour, which is probably challenging the assumption that ethane acts like an ideal gas. But you really don’t have much option here!

Nevertheless, from the ideal gas equation you can derive that 1 gram mole of an ideal gas at STP occupies 22.4 litres. Therefore 10 litres are equivalent to x gram moles of ethane …… I’ll leave you to do the arithmetic.

You now have the basis for quantifying the volume of CO2 produced from the number of gram moles in 10 litres of ethane at STP from the above equation that states that 2 gram moles of ethane produce 4 gram moles of CO2.

I hope this helps u