Question

calculate the volume of carbon monoxide at stp which contains equal number of oxygen atoms.As are present in 88g of CO2
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Answer 1

Answer:

88gCO2= 2 moles of CO2. One molecule consists of 2 oxygen atoms. 

No. of oxygen atoms =2×2×6.02×1023=24.08×1023

CO molecule has one oxygen atom. 

Mass of CO containing 24.08×1023 oxygen atoms 

=6.02×102328×24.08×1023=112g

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Answer 2

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HERE IS THE ANSWER,

88gCO

2

= 2 moles of CO

2

. One molecule consists of 2 oxygen atoms.

No. of oxygen atoms =2×2×6.02×10

23

=24.08×10

23

CO molecule has one oxygen atom.

Mass of CO containing 24.08×10

23

oxygen atoms

=

6.02×10

23

28

×24.08×10

23

=112g