Calculate the volume of Cl2 at STP produced during the electrolysis of MgCl2 which produces 5.4g Mg
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Answer:
From the formula of magnesium chloride (MgCl2):
One mole of MgCl2 gives 1 mole of Mg (24g) and one mole of Chlorine gas (Cl2)
One mole of gas occupies 22.4 liters (22400 cm³) at S.T.P.
⇒ 24g of Mg ≡ 22400 cm³ of Chlorine gas at S.T.P.
∴ 5.4 g of Mg ≡ (22400 x 5.4) ÷ 24
≡ 5040 cm³
Explanation:
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