Question

Calculate the volume of CO2 gas at STP which contain 10NA oxygen atom.​

Answer 1

Explanation:

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The molar mass of sodium chlorate is 106 g/mol.

Number of moles of sodium chlorate

= 212g / 106g/mol

=2 mol

The decomposition reaction of sodium chlorate is as shown.

2NaClO3 → 2NaCl+3O 2

The decomposition of 2 moles of sodium chlorate gives 3 moles of oxygen.

1 mole of oxygen at STP occupies a volume of 22.4 L.

3 moles of oxygen at STP will occupy a volume of 3×22.4=67.2 L.

Answer 2

The molar mass of sodium chlorate is 106 g/mol.

Number of moles of sodium chlorate

= 212g / 106g/mol

=2 mol

The decomposition reaction of sodium chlorate is as shown.

2NaClO3 → 2NaCl+3O 2

The decomposition of 2 moles of sodium chlorate gives 3 moles of oxygen.

1 mole of oxygen at STP occupies a volume of 22.4 L.

3 moles of oxygen at STP will occupy a volume of 3×22.4=67.2 L .