Question

calculate the volume of CO2 gas produced at STP by the combustion of 48 grams of CH4 ​

Answer 1

Answer:

Explanation:

cH4 + 2O2 = CO2 + 2H2O

16 g methane give 44 g of CO2

= (44/16) x 48

= 132 g of CO

Answer 2

Answer:

72 cubic decimeter.

Explanation:

Balanced chemical equation for the reaction:

CH4 + 4O2→CO2 +2H2O

Molar mass of CH4= 12+4=16

Moles of 48g of CH4= 48/16=3

Ratio of CH4:CO2= 1:1

Therefore 3moles of CH4 will produce 3 moles of CO2.

volume of 3 moles of CO2= 3*24= 72 dm cube.