Question

calculate the volume of CO2 gas released when 10g of CACO3 decomposes at STP​

Answer 1

The volume of gas produced is 2.24 L.

• The decomposition reaction of calcium carbonate is given below.
• CaCO3 ------> CO2 + CaO
• Now calculate the molar mass of calcium carbonate i.e. CaCO3
• Molar mass of CaCO3 is = 40 + 12 + 16 x 3 = 100g
• As we know that 100g of CaCO3 produces 1 mol of carbon dioxide CO2 i.e. 22.4 L
• Now 10 g of CaCO3 will produce 22.4 / 100 x 10 = 2.24 L

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