Question

Calculate the volume of co2 liberated during the combustion of 570g of octane at stp

Answer 1

Answer:

The balanced chemical reaction is C

3

H

8

+5O

2

→3CO

2

+4H

2

O.

1 mol (22.4 L at STP) of propane produces 3 mol (3×22.4 L at STP) of CO

2

.

Thus, 100 cm

3

of propane at STP will produce

22.4

100cm

3

×3×22.4L=300cm

3

at STP of CO

2