Question

Calculate the volume of CO2 produced at STP on the decomposition of 20g MgCO3 which is 42% pure. please it's urgent give write answer only then marked as brainliest otherwise reported​

Answer 1

Answer:

Decomposition of CaCO3

⇒CaCO3=CaO+CO2

⇒1mole=1mole+1mole

⇒100gm=56gm+44gm  

∴For 20gm of CaCO3

⇒20gm=11.5gm+8.8gm

but qn is to find the volume of CO2

1mole=22.4l

44gm=22.4l

8.8gm=4.48l

Explanation:

Answer 2

Answer:

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